1) х ≥ 5
[5; + бесконечность)
2)х²-2х-15<0
(х + 3)(х - 5) < 0
х¹ = -3
х² = 5
(-3; 5)
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1) х ≥ 5
[5; + бесконечность)
2)х²-2х-15<0
(х + 3)(х - 5) < 0
х¹ = -3
х² = 5
(-3; 5)