Объяснение:
FeCl2 + 2NaOH = 2NaCl + Fe(OH)2↓
n(FeCl2)=m/M=25.4/127=0.2mol
n(FeCl2)=n(Fe(OH)2)=0.2mol
m(Fe(OH)2)=n×M=0.2×(56+2×(16+1))=18gr
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Объяснение:
FeCl2 + 2NaOH = 2NaCl + Fe(OH)2↓
n(FeCl2)=m/M=25.4/127=0.2mol
n(FeCl2)=n(Fe(OH)2)=0.2mol
m(Fe(OH)2)=n×M=0.2×(56+2×(16+1))=18gr