[tex]\displaystyle\bf\\\Big(\frac{3}{2} \Big)^{2} :\Big(-\frac{9}{4}\Big)\cdot\Big(\frac{3}{2}\Big)^{0} \cdot\frac{2}{3} =\underbrace{-\frac{9}{4} \cdot\frac{4}{9}} _{-1}\cdot 1\cdot\frac{2}{3} =-\frac{2}{3}[/tex]