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[tex]2) \\ 9.4y + (2x - 11 \frac{1}{4} y) - 3 \frac{5}{9} x = 9 \frac{4}{10} y + 2x - \\ - 11 \frac{1}{4} y - 3 \frac{5}{9} x = \frac{94}{10} y + 2x - \frac{45}{4} y - \\ - \frac{32}{9} x = \frac{188y - 225y}{20} + \frac{18x - 32x}{9} = \\ = - \frac{37}{20} y - \frac{14}{9} x = - 1 \frac{17}{20} y - 1 \frac{5}{9} x[/tex]