[tex]\displaystyle\bf\\\left \{ {{(x-3)^{2} > x^{2} -3 } \atop {\dfrac{x}{2} > x+0,5 }} \right.\\\\\\\left \{ {{x^{2} -6x+9 > x^{2}-3 } \atop {\dfrac{x}{2}\cdot 2 > x\cdot 2+0,5\cdot 2 }} \right.\\\\\\\left \{ {{x^{2} -6x-x^{2} > -3-9} \atop {x > 2x+1}} \right.\\\\\\\left \{ {{-6x > -12} \atop {-x > 1}} \right.\\\\\\\left \{ {{x < 2} \atop {x < -1}} \right. \\\\\\Otvet:x\in\Big(-\infty \ ; \ -1\Big)[/tex]