Ответ:

1) 3х

2y

2) 2ху

5

3) n

16b

4)ײ

a

5) 2+a

c

Verified answer

[tex]\displaystyle\bf\\1)\\\\\frac{3x}{10y^{4} } :\frac{1}{5y^{3} } =\frac{3x}{10y^{4} } \cdot 5y^{3} =\frac{3x\cdot 5y^{3} }{2y\cdot 5y^{3} } =\frac{3x}{2y} \\\\\\2)\\\\\frac{6x^{2} }{5y^{2} } :\frac{3x}{y^{3} } =\frac{6x^{2} }{5y^{2} } \cdot \frac{y^{3} }{3x} =\frac{3x\cdot 2x\cdot y^{2} \cdot y}{5\cdot y^{2}\cdot 3x } =\frac{2xy}{5} \\\\\\3)\\\\\frac{9b^{3} }{20n^{2} } :\frac{36b^{4} }{5n^{3} } =\frac{9b^{3} \cdot 5n^{2} \cdot n}{5n^{2} \cdot n\cdot 9b^{3} \cdot 4b} =\frac{1}{4b}[/tex]

[tex]\displaystyle\bf\\4)\\\\\frac{x^{3} }{ab+ac}:\frac{x}{b+c} =\frac{x^{3} }{a\cdot(b+c)} \cdot\frac{b+c}{x} =\frac{x^{2} \cdot x\cdot(b+c)}{a\cdot(b+c)\cdot x} =\frac{x^{2} }{a} \\\\\\5)\\\\\frac{4-a^{2} }{c^{4} } :\frac{2-a}{c^{3} } =\frac{(2-a)(2+a)}{c^{3}\cdot c }\cdot\frac{c^{3} }{2-a} =\frac{2+a}{c}[/tex]