Home
О нас
Products
Services
Регистрация
Войти
Поиск
vikoshkaa
@vikoshkaa
June 2023
1
5
Report
срочно дам 50 баллов
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
msemkova16
1.P2O5(V II)
KCL (I. I)
Mn2O7(VII II)
K2O(I II)
Ag2O(I II)
P3N5 (V III)
3. KCL=39+35=74
R2O5= 31*2+16*5=142
Fe(OH)2=56+(1+16)*2=90
Al(NO3)2=27+(14+16*3)*2=166
Na3PO4=23*3+31+16*4=164
4. Mr(N2O5) = 108
W(N) = (Ar(N) * 2) / Mr(N2O5) = (14 * 2) / 108 = 0.25926 = 25.926%
W(O) = (Ar(O) * 5) / Mr(N2O5) = (16 * 5) / 108 = 0.74074 = 74.074%
Ответ: W(N) = 25.926%; W(O) = 74.074%
Mr (H3PO4) = 3 Ar (H) + Ar (P) + 4 Ar (O) = 3 * 1 + 31 + 4 * 16 = 98 г/моль
Находим массовые доли элементов :
W (H) = ( 3 Ar (H) : Mr (H3PO4)) * 100 = ((3 * 1) : 98) * 100 = 3,06 %
W (P) = (Ar (P) : Mr (H3PO4)) * 100 = (31 : 98) * 100 = 31,63 %
W (O) = (4 Ar (O) : Mr (H3PO4)) * 100 = ((4 * 16) : 98) * 100 = 65,31 %
0 votes
Thanks 0
More Questions From This User
See All
vikoshkaa
June 2023 | 0 Ответы
50 649c29f9e02c4
Answer
vikoshkaa
February 2023 | 0 Ответы
50 63e5d90731260
Answer
×
Report "срочно дам 50 баллов"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
KCL (I. I)
Mn2O7(VII II)
K2O(I II)
Ag2O(I II)
P3N5 (V III)
3. KCL=39+35=74
R2O5= 31*2+16*5=142
Fe(OH)2=56+(1+16)*2=90
Al(NO3)2=27+(14+16*3)*2=166
Na3PO4=23*3+31+16*4=164
4. Mr(N2O5) = 108
W(N) = (Ar(N) * 2) / Mr(N2O5) = (14 * 2) / 108 = 0.25926 = 25.926%
W(O) = (Ar(O) * 5) / Mr(N2O5) = (16 * 5) / 108 = 0.74074 = 74.074%
Ответ: W(N) = 25.926%; W(O) = 74.074%
Mr (H3PO4) = 3 Ar (H) + Ar (P) + 4 Ar (O) = 3 * 1 + 31 + 4 * 16 = 98 г/моль
Находим массовые доли элементов :
W (H) = ( 3 Ar (H) : Mr (H3PO4)) * 100 = ((3 * 1) : 98) * 100 = 3,06 %
W (P) = (Ar (P) : Mr (H3PO4)) * 100 = (31 : 98) * 100 = 31,63 %
W (O) = (4 Ar (O) : Mr (H3PO4)) * 100 = ((4 * 16) : 98) * 100 = 65,31 %