Ответ:
Сравнить значения выражений.
[tex]\bf 1)\ \ \Big((\sqrt3)^{\sqrt2\ \ ,\ \ )}\Big)^{\sqrt2}=(\sqrt3)^2=3\ < \ 3^{1,5}\\\\\\2)\ \ \Big(\dfrac{1}{6}\Big)^{\sqrt5}=\dfrac{1}{6^{\sqrt{5}}}\ \ ,\ \ 6^{-2,25}=\dfrac{1}{6^{2,25}}\\\\\sqrt5\approx 2,24 < 2,25\ \ \Rightarrow \ \ \ \dfrac{1}{6^{\sqrt5}} > \dfrac{1}{6^{2,25}}[/tex]
[tex]\displaystyle \bf 3)\ \ (7-4\sqrt3)^{-3,5}=\frac{1}{(7-4\sqrt3)^{3,5}}\approx 1,008 > \ (7-4\sqrt3)^{3,5}\approx 0,00001\\\\\\3)\ \ (5+2\sqrt6)^{3,3}\approx 1,93\ > \ (5+2\sqrt6)^{-3,1}=\frac{1}{(5+2\sqrt6)^{3,1}}\approx 0,0008[/tex]
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Ответ:
Сравнить значения выражений.
[tex]\bf 1)\ \ \Big((\sqrt3)^{\sqrt2\ \ ,\ \ )}\Big)^{\sqrt2}=(\sqrt3)^2=3\ < \ 3^{1,5}\\\\\\2)\ \ \Big(\dfrac{1}{6}\Big)^{\sqrt5}=\dfrac{1}{6^{\sqrt{5}}}\ \ ,\ \ 6^{-2,25}=\dfrac{1}{6^{2,25}}\\\\\sqrt5\approx 2,24 < 2,25\ \ \Rightarrow \ \ \ \dfrac{1}{6^{\sqrt5}} > \dfrac{1}{6^{2,25}}[/tex]
[tex]\displaystyle \bf 3)\ \ (7-4\sqrt3)^{-3,5}=\frac{1}{(7-4\sqrt3)^{3,5}}\approx 1,008 > \ (7-4\sqrt3)^{3,5}\approx 0,00001\\\\\\3)\ \ (5+2\sqrt6)^{3,3}\approx 1,93\ > \ (5+2\sqrt6)^{-3,1}=\frac{1}{(5+2\sqrt6)^{3,1}}\approx 0,0008[/tex]