[tex] - x + 2 = \sqrt{x \\ } \\ \sqrt{x} = - x + 2 \\ x = 4 - 4x + x {}^{2} \\ x = 4 - 4x + x { }^{2} \\ x = 4 + 4x \times x {}^{2} = 0 \\ - (4 - x) + x \times (4 - x) = 0 \\ - (4 - x) \times (1 - x) = 0 \\ (4x) \times (1 - x) = 0 \\ 4 - x = 0 \\ 1 - x = 0 \\ x = 4 \\ x = 1[/tex]
если что обращайся, вот мой инст: zzeska_f
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
[tex] - x + 2 = \sqrt{x \\ } \\ \sqrt{x} = - x + 2 \\ x = 4 - 4x + x {}^{2} \\ x = 4 - 4x + x { }^{2} \\ x = 4 + 4x \times x {}^{2} = 0 \\ - (4 - x) + x \times (4 - x) = 0 \\ - (4 - x) \times (1 - x) = 0 \\ (4x) \times (1 - x) = 0 \\ 4 - x = 0 \\ 1 - x = 0 \\ x = 4 \\ x = 1[/tex]
если что обращайся, вот мой инст: zzeska_f