1. В
[tex]49 - 7x \geqslant 0 \\ - 7x \geqslant - 49 \: \: | \div ( - 7) \\ x \leqslant 7[/tex]
2. Б
[tex]\displaystyle\bf\\\left \{ {{3x - 15 < 0} \atop {6x - 2 \geqslant 10 }} \right. \\ \displaystyle\bf\\\left \{ {{3x < 15 \: \: | \div 3 } \atop {6x \geqslant 12 \: \: | \div 6}} \right. \\ \displaystyle\bf\\\left \{ {{x < 5} \atop {x \geqslant 2 }} \right. \\ \\ x \: \epsilon \: [2; \: 5)[/tex]
3. Б
[tex]q = \frac{b_{n}}{b_{n - 1}} = \frac{b_{8}}{b_{7}} = \frac{ 9}{ - 3} = - 3[/tex]
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Answers & Comments
1. В
[tex]49 - 7x \geqslant 0 \\ - 7x \geqslant - 49 \: \: | \div ( - 7) \\ x \leqslant 7[/tex]
2. Б
[tex]\displaystyle\bf\\\left \{ {{3x - 15 < 0} \atop {6x - 2 \geqslant 10 }} \right. \\ \displaystyle\bf\\\left \{ {{3x < 15 \: \: | \div 3 } \atop {6x \geqslant 12 \: \: | \div 6}} \right. \\ \displaystyle\bf\\\left \{ {{x < 5} \atop {x \geqslant 2 }} \right. \\ \\ x \: \epsilon \: [2; \: 5)[/tex]
3. Б
[tex]q = \frac{b_{n}}{b_{n - 1}} = \frac{b_{8}}{b_{7}} = \frac{ 9}{ - 3} = - 3[/tex]