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anyyaman
@anyyaman
June 2022
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50 баллов
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Verified answer
∛(12-x) +∛(14+x) =2
∛(12-x)=a ∛(14+x)=b ⇔a+b=2
[∛(12-x) +∛(14+x)]³=2³
(12-x)+3 a²b+3ab²+14+x=8
26+3ab(a+b)=8
3ab·2=-18 ab= - 3
тогда
a+b=2
ab=-3 ⇔1) a=3 b=-1 2)a=-1 b=3
1)∛(12-x)=3 12-x=27 x=-15
∛(14-15)=-1 =b
2) ∛(12-x)=-1 12-x=-1 x=13
∛(14+13)=3 =b
x1=-15
x2=15
1 votes
Thanks 1
anyyaman
Почему когда проверяешь и ставишь х1,х2 то не выходит 2?
anyyaman
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Answers & Comments
Verified answer
∛(12-x) +∛(14+x) =2∛(12-x)=a ∛(14+x)=b ⇔a+b=2
[∛(12-x) +∛(14+x)]³=2³
(12-x)+3 a²b+3ab²+14+x=8
26+3ab(a+b)=8
3ab·2=-18 ab= - 3
тогда
a+b=2
ab=-3 ⇔1) a=3 b=-1 2)a=-1 b=3
1)∛(12-x)=3 12-x=27 x=-15
∛(14-15)=-1 =b
2) ∛(12-x)=-1 12-x=-1 x=13
∛(14+13)=3 =b
x1=-15
x2=15