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LizaKashtanka
@LizaKashtanka
March 2022
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50 баллов. С решением
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daynVassya
J3 = J2 - последовательное соединение.
По закону Ома:
J3 = U3/R3.
J3
=
J2
= 20/4 =
5 A.
U2 = J2*R2.
U2
= 5*8 =
40 B
.
U1 = U2 + U3 - параллельное соединение.
U1
= 20 + 40 =
60 B.
J1 = U1/R1.
J1
= 60/6 =
10 A.
J4 = J5 = J1 + J2.
J4
=
J5
=
5 + 10 =
15 A.
U4 = J4*R4.
U4
= 15*14 =
210 B
.
U5 = J5*R5.
U5
= 15*12 =
180 B
.
J = J1 + J2 = J4 = J5.
J
=
15 A.
R = R4 + R5 + (1/R1 + 1/(R2 + R3))^-1.
R
=
30 Ом.
U = J*R.
U
= 15*30 =
450 B.
2 votes
Thanks 1
LizaKashtanka
Большое спасибо))
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Answers & Comments
По закону Ома:
J3 = U3/R3.
J3 = J2 = 20/4 = 5 A.
U2 = J2*R2.
U2 = 5*8 = 40 B.
U1 = U2 + U3 - параллельное соединение.
U1 = 20 + 40 = 60 B.
J1 = U1/R1.
J1 = 60/6 = 10 A.
J4 = J5 = J1 + J2.
J4 = J5 = 5 + 10 = 15 A.
U4 = J4*R4.
U4 = 15*14 = 210 B.
U5 = J5*R5.
U5 = 15*12 = 180 B.
J = J1 + J2 = J4 = J5.
J = 15 A.
R = R4 + R5 + (1/R1 + 1/(R2 + R3))^-1.
R = 30 Ом.
U = J*R.
U = 15*30 = 450 B.