I.
C + 2H2 → CH4
M (C) = 12 г/моль
6 / 12 = X / 22,4
X = 6 × 22,4 / 12 = 11,2 л
II.
2CO + 2O2 → 2CO2
6 / 2 = X / 2
X = 6 × 2 / 2 = 6 л
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Answers & Comments
I.
C + 2H2 → CH4
M (C) = 12 г/моль
6 / 12 = X / 22,4
X = 6 × 22,4 / 12 = 11,2 л
II.
2CO + 2O2 → 2CO2
6 / 2 = X / 2
X = 6 × 2 / 2 = 6 л