Ответ:
Объяснение:
1) f(x)=2sinx*cosx=sin2x
f'(x)=sin2x=2cos2x (sin'u=u'cosu)
2) f(x)=2sinx(cosx+1)=2sinx*cosx+2sinx=sin2x+2sinx
f'(x)=·2cos2x+2cosx=2cos2x+2cosx
3) f(x)=sinx*ctgx=sinx*cosx/sinx=cosx
f'(x)=-sinx
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Ответ:
Объяснение:
1) f(x)=2sinx*cosx=sin2x
f'(x)=sin2x=2cos2x (sin'u=u'cosu)
2) f(x)=2sinx(cosx+1)=2sinx*cosx+2sinx=sin2x+2sinx
f'(x)=·2cos2x+2cosx=2cos2x+2cosx
3) f(x)=sinx*ctgx=sinx*cosx/sinx=cosx
f'(x)=-sinx