Ответ:
дано
m(ppa H2SO4) = 150 g
W(H2SO4) = 10%
m(ppa NaOH) = 100 g
W(NaOH) = 5%
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m(Na2SO4) - ?
m(H2SO4) = 150*10% / 100% = 15 g
M(H2SO4) = 98 g/mol
n(H2SO4) = m/M = 15 / 98 = 0.15 mol
m(NaOH)= 100*5% / 100% = 5 g
M(NaOH) = 40 g/mol
n(NaOH) = m/M = 5 / 40 = 0,125 mol
n(H2SO4) > n(NaOH)
H2SO4+2NaOH-->Na2SO4+2H2O
2n(NaOH) = n(Na2SO4)
n(Na2SO4) = 0.125 / 2 = 0.0625 mol
M(Na2SO4) = 142 g/mol
m(Na2SO4) = n*M = 0.0625 *142 = 8,875 g
ответ 8.875 гр
Объяснение:
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Answers & Comments
Ответ:
дано
m(ppa H2SO4) = 150 g
W(H2SO4) = 10%
m(ppa NaOH) = 100 g
W(NaOH) = 5%
-----------------------
m(Na2SO4) - ?
m(H2SO4) = 150*10% / 100% = 15 g
M(H2SO4) = 98 g/mol
n(H2SO4) = m/M = 15 / 98 = 0.15 mol
m(NaOH)= 100*5% / 100% = 5 g
M(NaOH) = 40 g/mol
n(NaOH) = m/M = 5 / 40 = 0,125 mol
n(H2SO4) > n(NaOH)
H2SO4+2NaOH-->Na2SO4+2H2O
2n(NaOH) = n(Na2SO4)
n(Na2SO4) = 0.125 / 2 = 0.0625 mol
M(Na2SO4) = 142 g/mol
m(Na2SO4) = n*M = 0.0625 *142 = 8,875 g
ответ 8.875 гр
Объяснение: