Ответ:
C+Al=Al4C3
m(Al) =100*40%/100%=40г
V(С)=50/12=4.2 моль
V(Al)=100/27=3.7моль
50/12=x/144 x=600
m(Al4C3)=600 г
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Ответ:
C+Al=Al4C3
m(Al) =100*40%/100%=40г
V(С)=50/12=4.2 моль
V(Al)=100/27=3.7моль
50/12=x/144 x=600
m(Al4C3)=600 г