501,503 решите плз!!!!!. Created by NaHal. algebra-ru

N501. а)_/1.44/3.61=_/1.2/1.9. б)_/11 1/9=_/100/9=10/3 N503. б)_/32*128=_/4096=64. а)_/50*98=_/4900=70

501,503 решите плз!!!!!...

lisinaaliona Номер 501:
а) $\sqrt{\frac{1,44}{3,61}}= \frac{1,2}{1,9}$
б) $\sqrt{11\frac{1}{9}}= \sqrt{\frac{100}{9}}= \frac{10}{3}$
в) $\sqrt{1 \frac{13}{36}*3 \frac{13}{36}}= \sqrt{ \frac{49}{36}* \frac{121}{36}}= \sqrt{ \frac{49}{36}}* \sqrt{ \frac{121}{36}} = \frac{7}{6}* \frac{11}{6}= \frac{77}{36}$
г) $\sqrt{ \frac{1}{144}* 2\frac{12}{49}}= \sqrt{ \frac{1}{144}}* \sqrt{ \frac{100}{49}} = \frac{1}{12}* \frac{10}{7}= \frac{10}{84}$
д) $\sqrt{ \frac{1}{9}*0,04*64 }= \sqrt{ \frac{1}{9}}* \sqrt{ \frac{4}{100}}* \sqrt{64}= \frac{1}{3}* \frac{2}{10}*8= \frac{16}{30}$
е) $\sqrt{ 1\frac{9}{16}* 2\frac{1}{4}*2 \frac{7}{9}}= \sqrt{ \frac{25}{16}}* \sqrt{\frac{9}{4}}* \sqrt{ \frac{25}{9} }= \frac{5}{4}* \frac{3}2}* \frac{5}{3}= \frac{75}{24}$
Номер 503:
а) $\sqrt{50*98}=5 \sqrt{2}*7 \sqrt{2}=35*2=70$
б) $\sqrt{32*128}=4 \sqrt{2}*8 \sqrt{2}=32*2=64$
в) $\sqrt{2,5*12,1}= \sqrt{30,25}=5,5$
г) $\sqrt{17*51*27}= \sqrt{17}* \sqrt{3}* \sqrt{17}*3 \sqrt{3}=17*3*3=153$
д) $\sqrt{3,2*7,2*49}= \sqrt{23,04}*7=48*7=336$
е-не получается

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