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dcheremnyx2011
@dcheremnyx2011
July 2022
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Найдите tg2a, если (sina-4cosa) / (3sina+4cosa)=3 / 5
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kalbim
Verified answer
5*(sina - 4cosa) = 3*(3sina + 4cosa)
5sina - 20cosa = 9sina + 12cosa
-4sina = 32cosa
tga = -8
tg(2a) = 2tg(a)/(1 - tg^2(a)) = 2*(-8)/(1 - 64) = 16/63
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Answers & Comments
Verified answer
5*(sina - 4cosa) = 3*(3sina + 4cosa)5sina - 20cosa = 9sina + 12cosa
-4sina = 32cosa
tga = -8
tg(2a) = 2tg(a)/(1 - tg^2(a)) = 2*(-8)/(1 - 64) = 16/63