[tex]\displaystyle (4\frac{1}{6}m+11\frac{1}{4})*\frac{4}{15}=\frac{2}{3}m+5\frac{2}{3}\\ \\(\frac{25}{6}m+\frac{45}{4})*\frac{4}{15}=\frac{2}{3}m+\frac{17}{3}\\ \\\frac{10}{9}m+3=\frac{2}{3}m+\frac{17}{3}\\ \\10m+27=6m+51\\ 10m-6m=51-27\\ 4m=24\\ m=6[/tex]
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[tex]\displaystyle (4\frac{1}{6}m+11\frac{1}{4})*\frac{4}{15}=\frac{2}{3}m+5\frac{2}{3}\\ \\(\frac{25}{6}m+\frac{45}{4})*\frac{4}{15}=\frac{2}{3}m+\frac{17}{3}\\ \\\frac{10}{9}m+3=\frac{2}{3}m+\frac{17}{3}\\ \\10m+27=6m+51\\ 10m-6m=51-27\\ 4m=24\\ m=6[/tex]