[tex]\dfrac{2\,\left(4\,x+5\right)}{5}=\dfrac{2\,\left(x+11\right)}{5}\Leftrightarrow \dfrac{8\,x}{5}+2=\dfrac{2\,x}{5}+\dfrac{22}{5}\Leftrightarrow \dfrac{6\,x}{5}=\dfrac{12}{5}\Rightarrow x=2[/tex]