Відповідь:
1) (2x+9)/4-(x-2)/6 = 3
(3(2x+9)-2(x-2))/12 = 3
6x+27-2x+4-36 = 0
4x+31-36 = 0
x = 5/4
x = 5/4 або 1,25
2) (2x-3)(x+7)=(x-4)(2x+3)+3
2x^2+14x-3x-21 = 2x^2+3x-8x-12+3
16x-21+9 = 0
16x = 12
x = 12/16
x = 3/4 або 0,75
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Answers & Comments
Відповідь:
1) (2x+9)/4-(x-2)/6 = 3
(3(2x+9)-2(x-2))/12 = 3
6x+27-2x+4-36 = 0
4x+31-36 = 0
x = 5/4
x = 5/4 або 1,25
2) (2x-3)(x+7)=(x-4)(2x+3)+3
2x^2+14x-3x-21 = 2x^2+3x-8x-12+3
16x-21+9 = 0
16x = 12
x = 12/16
x = 3/4 або 0,75