[tex]\displaystyle\bf\\ODZ:\\\\\left \{ {{x > 0} \atop {x\neq 1}} \right. \\\\\\2\log_{3} x=2\log_{x} 3+3\\\\\\2\log_{3} x-\frac{2}{\log_{3} x} -3=0\\\\\\\log_{3} x=m \ , \ m\neq 0\\\\\\2m-\frac{2}{m} -3=0\\\\\\\frac{2m^{2} -3m-2}{m} =0\\\\\\2m^{2} -3m-2=0\\\\D=(-3)^{2} -4\cdot 2\cdot(-2)=9+16=25=5^{2} \\\\\\m_{1}=\frac{3-5}{4}=-\frac{1}{2} \\\\\\m_{2} =\frac{3+5}{4} =2\\\\\\1)\\\\\log_{3} x=-\frac{1}{2} \\\\x_{1} =3^{-\frac{1}{2} }=\frac{1}{\sqrt{3} } \\\\2)[/tex]
[tex]\displaystyle\bf\\log_{3} x=2\\\\x_{2} =3^{2}=9\\\\\\Otvet \ : \ \frac{1}{\sqrt{3} } \ \ , \ \ 9[/tex]
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[tex]\displaystyle\bf\\ODZ:\\\\\left \{ {{x > 0} \atop {x\neq 1}} \right. \\\\\\2\log_{3} x=2\log_{x} 3+3\\\\\\2\log_{3} x-\frac{2}{\log_{3} x} -3=0\\\\\\\log_{3} x=m \ , \ m\neq 0\\\\\\2m-\frac{2}{m} -3=0\\\\\\\frac{2m^{2} -3m-2}{m} =0\\\\\\2m^{2} -3m-2=0\\\\D=(-3)^{2} -4\cdot 2\cdot(-2)=9+16=25=5^{2} \\\\\\m_{1}=\frac{3-5}{4}=-\frac{1}{2} \\\\\\m_{2} =\frac{3+5}{4} =2\\\\\\1)\\\\\log_{3} x=-\frac{1}{2} \\\\x_{1} =3^{-\frac{1}{2} }=\frac{1}{\sqrt{3} } \\\\2)[/tex]
[tex]\displaystyle\bf\\log_{3} x=2\\\\x_{2} =3^{2}=9\\\\\\Otvet \ : \ \frac{1}{\sqrt{3} } \ \ , \ \ 9[/tex]