Ответ:
Объяснение:
1) [tex]\frac{a}{4a+b}[/tex] = [tex]\frac{3a}{3(4a+b)}[/tex] = [tex]\frac{3a}{12a+3b}[/tex]
2)[tex]\frac{1}{x-4y}[/tex] = [tex]\frac{1*(x+4y)}{(x-4y)(x+4y)}[/tex] = [tex]\frac{x+4y}{x^{2} -16y^{2} }[/tex]
3) [tex]\frac{2x}{5x+y}[/tex] = [tex]\frac{2x(5x+y)}{(5x+y)(5x+y)}[/tex] = [tex]\frac{2x(5x+y)}{(5x+y)^{2} }[/tex] = [tex]\frac{10x^{2} +2xy}{25x^{2} +2*5xy+y^{2} }[/tex] = [tex]\frac{10x^{2} +2xy}{25x^{2} +10xy+y^{2} }[/tex]
4) [tex]\frac{4b}{2-3b}[/tex] = [tex]\frac{4b(2-3b)}{(2-3b)(2-3b)}[/tex] = [tex]\frac{4b(2-3b)}{(2-3b)^{2} }[/tex] = [tex]\frac{8b-12b^{2} }{4-2*2*3b+9b^{2} }[/tex] = [tex]\frac{8b-12b^{2} }{4-12b+9b^{2} }[/tex]
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Answers & Comments
Ответ:
Объяснение:
1) [tex]\frac{a}{4a+b}[/tex] = [tex]\frac{3a}{3(4a+b)}[/tex] = [tex]\frac{3a}{12a+3b}[/tex]
2)[tex]\frac{1}{x-4y}[/tex] = [tex]\frac{1*(x+4y)}{(x-4y)(x+4y)}[/tex] = [tex]\frac{x+4y}{x^{2} -16y^{2} }[/tex]
3) [tex]\frac{2x}{5x+y}[/tex] = [tex]\frac{2x(5x+y)}{(5x+y)(5x+y)}[/tex] = [tex]\frac{2x(5x+y)}{(5x+y)^{2} }[/tex] = [tex]\frac{10x^{2} +2xy}{25x^{2} +2*5xy+y^{2} }[/tex] = [tex]\frac{10x^{2} +2xy}{25x^{2} +10xy+y^{2} }[/tex]
4) [tex]\frac{4b}{2-3b}[/tex] = [tex]\frac{4b(2-3b)}{(2-3b)(2-3b)}[/tex] = [tex]\frac{4b(2-3b)}{(2-3b)^{2} }[/tex] = [tex]\frac{8b-12b^{2} }{4-2*2*3b+9b^{2} }[/tex] = [tex]\frac{8b-12b^{2} }{4-12b+9b^{2} }[/tex]