[tex]1) \: \: \: \: \: \frac{ {10p}^{2} - n }{2p} - 5p = \frac{ {10p}^{2} - 10 {p}^{2} - n }{2p} = - \frac{n}{2p \\ } [/tex]
[tex]2) \: \: \: \: \: \frac{2a}{ {b}^{2} - 4 {a}^{2} } + \frac{1}{2a - b} = \frac{2a}{ - (2a - b)(2a + b)} + \frac{1}{2a - b} = \frac{2a - 2a - b}{ - (2a - b)(2a + b)} = \frac{ - b}{ - (2a - b)(2a + b)} = \frac{b}{4 {a}^{2} - {b}^{2} } [/tex]
[tex]3) \: \: \: \: \: \frac{25}{ {x}^{2} - 5x } - \frac{x}{x - 5} + \frac{x + 5}{x} = \frac{25}{x(x - 5)} - \frac{x}{x - 5} + \frac{x + 5}{x} = \frac{25 - {x}^{2} + {x}^{2} - 25}{x(x - 5)} = \frac{0}{x(x - 5)} = 0[/tex]
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[tex]1) \: \: \: \: \: \frac{ {10p}^{2} - n }{2p} - 5p = \frac{ {10p}^{2} - 10 {p}^{2} - n }{2p} = - \frac{n}{2p \\ } [/tex]
[tex]2) \: \: \: \: \: \frac{2a}{ {b}^{2} - 4 {a}^{2} } + \frac{1}{2a - b} = \frac{2a}{ - (2a - b)(2a + b)} + \frac{1}{2a - b} = \frac{2a - 2a - b}{ - (2a - b)(2a + b)} = \frac{ - b}{ - (2a - b)(2a + b)} = \frac{b}{4 {a}^{2} - {b}^{2} } [/tex]
[tex]3) \: \: \: \: \: \frac{25}{ {x}^{2} - 5x } - \frac{x}{x - 5} + \frac{x + 5}{x} = \frac{25}{x(x - 5)} - \frac{x}{x - 5} + \frac{x + 5}{x} = \frac{25 - {x}^{2} + {x}^{2} - 25}{x(x - 5)} = \frac{0}{x(x - 5)} = 0[/tex]