найдите корень уравнения х+3/7=2х-1/5
(х+3) ÷ 7 = (2х-1) ÷ 5
5(x+3) = 7(2x-1)
5x + 15 = 14x-7
5x - 14x = -7 - 15
-9x = -22
x = 22 ÷ 9
x = 2 ⁴/₉
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(х+3) ÷ 7 = (2х-1) ÷ 5
5(x+3) = 7(2x-1)
5x + 15 = 14x-7
5x - 14x = -7 - 15
-9x = -22
x = 22 ÷ 9
x = 2 ⁴/₉