Ответ:
Объяснение:
1) III I IV I IV II I V II
NH3 CCl4 SO2 HNO3
2)
a)Pb2O Al2O3 B2O3 SO3 K2O Mn2O7
б) CuCl2 FeCl2 FeCl3 SiCl4 ZnCl2 PCl5
3)
Mr(CO2)= 12 + 16 * 2 = 44
Mr(CuO) = 64 + 16 = 80
Mr(Na2S) = 23 * 2 + 32 = 78
Mr(CaCO3) = 40 + 12 + 16 * 3 = 100
Mr(CH4) = 12 + 1 * 4 = 16
Mr(ZnO) = 65 + 16 = 83
Mr(FeS) = 56 + 32 = 88
Mr(H2SO4) =1 * 2 + 32 + 16 * 4 = 98
Mr(CuCl2) = 64 + 35,5 * 2 = 135
4)
М(Н2) : М(О) = 2 : 16 = 1 : 8
М(S) : (О2) = 32 : 32 = 1 : 1
M(H) : М(N) : М(O3) = 1 : 14 : 48
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Answers & Comments
Ответ:
Объяснение:
1) III I IV I IV II I V II
NH3 CCl4 SO2 HNO3
2)
a)Pb2O Al2O3 B2O3 SO3 K2O Mn2O7
б) CuCl2 FeCl2 FeCl3 SiCl4 ZnCl2 PCl5
3)
Mr(CO2)= 12 + 16 * 2 = 44
Mr(CuO) = 64 + 16 = 80
Mr(Na2S) = 23 * 2 + 32 = 78
Mr(CaCO3) = 40 + 12 + 16 * 3 = 100
Mr(CH4) = 12 + 1 * 4 = 16
Mr(ZnO) = 65 + 16 = 83
Mr(FeS) = 56 + 32 = 88
Mr(H2SO4) =1 * 2 + 32 + 16 * 4 = 98
Mr(CuCl2) = 64 + 35,5 * 2 = 135
4)
М(Н2) : М(О) = 2 : 16 = 1 : 8
М(S) : (О2) = 32 : 32 = 1 : 1
M(H) : М(N) : М(O3) = 1 : 14 : 48