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Nastya11043
@Nastya11043
August 2022
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найдите cos β, tg β и ctg β, если sin β 4/5
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bus171
Cos²β=1 - sin²
β
cosβ=√1-16/25=√9/25=3/5
tgβ=√(1-cos²β)/cosβ=√(1-9/25)/(3/5)=√16/25*5/3=4/√15=(4√15)/15
ctgβ=1/tgβ=√15/4
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Answers & Comments
cosβ=√1-16/25=√9/25=3/5
tgβ=√(1-cos²β)/cosβ=√(1-9/25)/(3/5)=√16/25*5/3=4/√15=(4√15)/15
ctgβ=1/tgβ=√15/4