1)

[tex] \frac{4 + 3x}{5} = - 8 \\ 4 + 3x = ( - 8) \times 5 \\ 4 + 3x = - 40 \\ 3x = - 40 - 4 \\ 3x = - 44 \\ x = \frac{ -44}{3} \\ x =- 14 \frac{2}{3} [/tex]

2)

[tex]3 \frac{1}{3} (3x - \frac{7}{20} ) - 8x = - 2.5 \\ \frac{10}{3} (3x - \frac{7}{20} ) - 8x = - \frac{5}{2} \\ \frac{10}{3} \times 3x - \frac{10}{3} \times \frac{7}{20 } - 8x = - \frac{5}{2} \\ 10x - \frac{7}{6} - 8x = - \frac{5}{2} \\ 2x = - \frac{5}{2} + \frac{7}{6} \\ 2 x = \frac{ - 15 + 7}{6} \\ 2x = \frac{ - 8}{6} \\ x = (- \frac{8}{6}) \times \frac{1}{2} \\ x = - \frac{2}{3} [/tex]

3)

[tex] - x \times |x - 3| = 0 \\ - x \times (x - 3) = 0 \\ - x = 0 \: \\ x_ 1 = 0 \\ x - 3 = 0 \\x_2 = 3[/tex]

нуу вот

Verified answer

Решение на прикреплённой фотографии