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Wahmurad
@Wahmurad
October 2021
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55г пропан толіқ жануы үшін оттектін қанша көлемі (қ.ж) қажет
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Alexei78
55g XL
С3H8+5O2-->3CO2+4H2O M(C3H8)=44 g/mol Vm=22.4L/mol
44 5*22.4
X=55*112 / 44=140 л
ответ 140 л
4 votes
Thanks 5
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Answers & Comments
С3H8+5O2-->3CO2+4H2O M(C3H8)=44 g/mol Vm=22.4L/mol
44 5*22.4
X=55*112 / 44=140 л
ответ 140 л