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ЕдИнОрОжКа46
@ЕдИнОрОжКа46
September 2021
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561 - подать в виде суммы
566 - подать в виде суммы
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sedinalana
Verified answer
561
1)x^4(a-1)-x²(a-1)=(a-1)(x^4-x²)=x²(a-1)(x²-1)=x²(a-1)(x-1)(x+1)
2)mn(m²-1)-m(m²-1)=(mn-m)(m²-1)=m(n-1)(m-1)9m+1)
3)y²(y-1)-(y-1)=(y-1)(y²-1)=(y-1)(y-1)(y+1)=(y-1)²(y+1)
4)(2m-1)(4m²+2m+1)-6m(2m-1)=(2m-1)(4m²+2m+1-6m)=
=(2m-1)(4m²-4m+1)=(2m-1)(2m-1)²=(2m-1)³
566
1)(t-6)(t³-10t+25)=(t-6)(t-5)²
2)(m+n)(m²-mn+n²)+(m-n)²=(m-n)(m²-mn+n²+m-n)
3)(a+b)²-(x+y)²=(a+b-x-y)(a+b+x+y)
2 votes
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Answers & Comments
Verified answer
5611)x^4(a-1)-x²(a-1)=(a-1)(x^4-x²)=x²(a-1)(x²-1)=x²(a-1)(x-1)(x+1)
2)mn(m²-1)-m(m²-1)=(mn-m)(m²-1)=m(n-1)(m-1)9m+1)
3)y²(y-1)-(y-1)=(y-1)(y²-1)=(y-1)(y-1)(y+1)=(y-1)²(y+1)
4)(2m-1)(4m²+2m+1)-6m(2m-1)=(2m-1)(4m²+2m+1-6m)=
=(2m-1)(4m²-4m+1)=(2m-1)(2m-1)²=(2m-1)³
566
1)(t-6)(t³-10t+25)=(t-6)(t-5)²
2)(m+n)(m²-mn+n²)+(m-n)²=(m-n)(m²-mn+n²+m-n)
3)(a+b)²-(x+y)²=(a+b-x-y)(a+b+x+y)