x — ∠F
x/4 — ∠P
x−54 — ∠K
Сумма углов треугольника = 180°:
[tex]x + \frac{x}{4} +x-54=180\\2x+\frac{x}{4}=234\\8x+x=936\\9x=936\\x=104[/tex]
∠F = 104°
∠P = 104/4 = 26°
∠K = 104-54 = 50°
Ответ: ∠F = 104°; ∠P = 26°; ∠K = 50°.
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x — ∠F
x/4 — ∠P
x−54 — ∠K
Сумма углов треугольника = 180°:
[tex]x + \frac{x}{4} +x-54=180\\2x+\frac{x}{4}=234\\8x+x=936\\9x=936\\x=104[/tex]
∠F = 104°
∠P = 104/4 = 26°
∠K = 104-54 = 50°
Ответ: ∠F = 104°; ∠P = 26°; ∠K = 50°.