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LiliyaMak
@LiliyaMak
July 2022
1
25
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В 1 л раствора содержится 2 г гидроксида калия. Вычислите рН раствора.
а) Lg 2/56; б) -Lg 2/56; в) 14-Lg 2/56; г) 14+Lg 2/56
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DashaNikitina451
n(KOH) = m/M = 2/56 = 0,04 моль
C(KOH) = n/V = 0,04/1 = 0,04 моль/л
KOH = K⁺ + OH⁻
[OH⁻] = C(KOH) = 0,04 моль/л
pOH = -lg[OH⁻]
pOH = -lg[0,04]
pOH =1
pH = 14-pOH = 13
pH = 14 - (-lg[0,04]) = 14 + lg(0,04) = 14-1 = 13 => г
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Answers & Comments
n(KOH) = m/M = 2/56 = 0,04 моль
C(KOH) = n/V = 0,04/1 = 0,04 моль/л
KOH = K⁺ + OH⁻
[OH⁻] = C(KOH) = 0,04 моль/л
pOH = -lg[OH⁻]
pOH = -lg[0,04]
pOH =1
pH = 14-pOH = 13
pH = 14 - (-lg[0,04]) = 14 + lg(0,04) = 14-1 = 13 => г