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sky333
@sky333
June 2022
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5*7^х-1+4*3^х+3^х+1-2*7^х=0(способ группировки)помогите
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nafanya2014
Verified answer
4*3^x +3^x+1=2*7^x -5*7^x-1)
3^x(4+3)=7^x(2-5*1/7)
3^x*7=7^x*9/7
(3/7)^x=9/49
x=2
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Answers & Comments
Verified answer
4*3^x +3^x+1=2*7^x -5*7^x-1)3^x(4+3)=7^x(2-5*1/7)
3^x*7=7^x*9/7
(3/7)^x=9/49
x=2