Ответ:

Объяснение:

[tex]a^6-4b^4= (a^3-2b^2)(a^3+2b^2)\\[/tex]

[tex]0.001a^3-27b^3 =(0.1a-3b)(0.01a^2+0.1a*3b+9b^2) =\\=(0.1a-3b)(0.01a^2+0.3ab+9b^2)\\[/tex]

[tex]0.8a^3+0.4a^2+0.4a^2 = 0.8a^3+0.8a^2=0.8a^2(a+1)[/tex]

-(2х+3^)^2+(x+5)(2x+5)=16

-(4x²+12x+9) +(2x²+15x+25)-16=0

2x²+15x+25-16 -4x² -12x-9 =0

-2x²+3x=0

x(3-2x)=0

x1=0      x2=1.5

x²-2x-35=0

D=4+35*1*4=144=12²

x1=(2+12)/2=7   x2=(2-12)/2=-5