1)
(а⁴в⁵)² : (а²в²)³ =
= а⁴°² в⁵°² : а²°³ в²°³ =
= а⁸в¹⁰ : а⁶в⁶ =
= а⁸⁻⁶ * в¹⁰⁻⁶ =
= а²в⁴,
при а = -0,5, в = 2:
(-0,5)² * 2⁴ = 0,25 * 16 = 4,
2)
(х⁷у⁴)³ : (х¹⁰у⁵)² =
= х⁷°³ у⁴°³ : х¹⁰°² у⁵°² =
= х²¹у¹² : х²⁰у¹⁰ =
= х²¹⁻²⁰ * у¹²⁻¹⁰ =
= х¹*у² = ху²,
при х = -3, у = 2/3:
-3 * (2/3)² = -3 * 4/9 = -4/3 = - 1 1/3
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
Verified answer
1)
(а⁴в⁵)² : (а²в²)³ =
= а⁴°² в⁵°² : а²°³ в²°³ =
= а⁸в¹⁰ : а⁶в⁶ =
= а⁸⁻⁶ * в¹⁰⁻⁶ =
= а²в⁴,
при а = -0,5, в = 2:
(-0,5)² * 2⁴ = 0,25 * 16 = 4,
2)
(х⁷у⁴)³ : (х¹⁰у⁵)² =
= х⁷°³ у⁴°³ : х¹⁰°² у⁵°² =
= х²¹у¹² : х²⁰у¹⁰ =
= х²¹⁻²⁰ * у¹²⁻¹⁰ =
= х¹*у² = ху²,
при х = -3, у = 2/3:
-3 * (2/3)² = -3 * 4/9 = -4/3 = - 1 1/3