Пошаговое объяснение:

[tex]\left \{ {{\frac{2x-1}{6}+\frac{x+2}{3}\geq \frac{x-8}{2}+x\ |*6 } \atop {2-2x > 0,5+0,5x\ |*2}} \right.\ \ \ \ \ \left \{ {{2x-1+2*(x+2)\geq 3*(x-8)+6*x} \atop {4-4x > 1+x}} \right.\ \ \ \ \ \left \{ {{2x-1+2x+4\geq 3x-24+6x} \atop {5x < 3\ |;5}} \right.[/tex]

[tex]\left \{ {{4x+3\geq 9x-24} \atop {x < 0,6}} \right. \ \ \ \ \left \{ {{5x\leq 27\ |:5} \atop {x\leq 0,6}} \right. \ \ \ \ \ \ \left \{ {{x\leq 5,4} \atop {x < 0,6}} \right. .[/tex]

Ответ: x∈(-∞;0,6).