[tex]\displaystyle\bf\\(a+3)^{2} -2a(3-4a)=a^{2} +6a+9-6a+8a^{2} =9a^{2} +9\\\\\\a=-\frac{1}{3} \\\\\\9a^{2} +9=9\cdot\Big(-\frac{1}{3} \Big)^{2} +9=9\cdot \frac{1}{9} +9=1+9=10\\\\\\Otvet: \ 10[/tex]
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[tex]\displaystyle\bf\\(a+3)^{2} -2a(3-4a)=a^{2} +6a+9-6a+8a^{2} =9a^{2} +9\\\\\\a=-\frac{1}{3} \\\\\\9a^{2} +9=9\cdot\Big(-\frac{1}{3} \Big)^{2} +9=9\cdot \frac{1}{9} +9=1+9=10\\\\\\Otvet: \ 10[/tex]