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nastilyaaa
@nastilyaaa
July 2022
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(5a-10)^2-(3a-8)+4a при а=6 ребят, плиз оч надо))
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maliya02
10а-20-3а+8+4а
11а-12
11*6-12
66-12=54
6 votes
Thanks 5
gorshckowashur1
Ответ:
(5a-10)^2-(3a-8)^2+4a
5a^2-100a+100-(9a^2-48a+64)+4a
5a^2-100a+100-9a^2+48a-64+4a
-4a^2-48a+36
Если а=6,то:
-4*6^2-48*6+36=
=-4*36-48*6+36=
=-144-288+36=-396
6 votes
Thanks 1
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Answers & Comments
11а-12
11*6-12
66-12=54
(5a-10)^2-(3a-8)^2+4a
5a^2-100a+100-(9a^2-48a+64)+4a
5a^2-100a+100-9a^2+48a-64+4a
-4a^2-48a+36
Если а=6,то:
-4*6^2-48*6+36=
=-4*36-48*6+36=
=-144-288+36=-396