Verified answer

Ответ:

[tex]\frac{3b^2+2}{2b^2}[/tex]

Пошаговое объяснение:

[tex]\frac{15b-2}{10b}+\frac{5+b}{5b^2}=\frac{b(15b-2)}{10b*b}+\frac{2(5+b)}{5b^2*2}=\frac{15b^2-2b}{10b^2}+\frac{10+2b}{10b^2}=\frac{15b^2-2b+10+2b}{10b^2}=\\\\=\frac{15b^2+10}{10b^2}=\frac{5(3b^2+2)}{10b^2}=\frac{3b^2+2}{2b^2}[/tex]