Приведите к тригонометрической функции угла из промежутка [0; p/2]
Cos 0,7p; sin 1,6p; ctg (-3p/7); tg (-9p/5 ).
Cos 0,7p; sin 1,6p; ctg (-3p/7); tg (-9p/5 ).
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Answers & Comments
sin(8pi/5)=sin(8pi/5-2pi)=sin(-2pi/5)=-sin(2pi/5) 0<2pi/5<2,5pi/5=pi/2
ctg(-3pi/7)=-ctg(3pi/7) 0<3pi/7<3,5pi/7=pi/2
tg(-9pi/5)=tg(-9pi/5+2pi)=tg(pi/5) 0<pi/5<2,5pi/5=pi/2