(5cos2a-sin2a) если tg=3...

Abzal228 @Abzal228

July 2022 1 4 Report

(3sin2a-4cos2a)/(5cos2a-sin2a) если tg=3

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sedinalana

Verified answer

Tga=3
cos²a=1:(1+tg²a)=1:(1+9)=1/10
cosa=1/√10
sina=√(1-cos²a)=√(1-1/10)=3/√10
sin2a=2sinacosa=2*3/√10*1/√10=0,6
cos2a=2cos²a-1=0,2-1=-0,8
(3sin2a-4cos2a)/(5cos2a-sin2a)=(1,8+3,2)/(-4-0,6)=5/(-4,6)=-25/23

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