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ladyshko
@ladyshko
August 2021
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sinb*cosb+2/5cos^2b+1
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sedinalana
Sinb*cosb+2=1/2*sin2b +2=(sin2b+4)/2
5cos²b+1=5*(1+cos2b)/2 +1=(5+5cos2b+2)/2=(7+5cos2b)/2
(sin2b+4)/2 : (7+5cos2b)/2=(sin2b+4)/2 *2/(7+5cos2b)=(sin2b+4)
/(7+5cos2b)
5 votes
Thanks 12
ladyshko
если тангенс бетта равен 2
ladyshko
а там тангенса нет
sedinalana
В условии тангенса нет.Задай новый вопрос
ladyshko
уже задала новый
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Answers & Comments
5cos²b+1=5*(1+cos2b)/2 +1=(5+5cos2b+2)/2=(7+5cos2b)/2
(sin2b+4)/2 : (7+5cos2b)/2=(sin2b+4)/2 *2/(7+5cos2b)=(sin2b+4)/(7+5cos2b)