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dimaevdokimov1
@dimaevdokimov1
July 2022
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Вычислить cos2a, если sins= 4/5
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tanylja
Cos 2α = 1 - 2 sin²α = 1 - 2 * (3/5)² = 1 - 2 * 9/25 = 1 - 18/25 = 7/25
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tanylja
По моему так
svetabessonova
Sind=sqrt(1-kos 2a)=3/5
tga=sina/cosa=3/5:(-4/5)=-3/4
cos2a=cos^2a-sin^2a=(-4/5)^2-(3/5)^2=7/25
1 votes
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Answers & Comments
tga=sina/cosa=3/5:(-4/5)=-3/4
cos2a=cos^2a-sin^2a=(-4/5)^2-(3/5)^2=7/25