Ответ:
Пошаговое объяснение:
№1
[tex]\frac{14}{93}[/tex]+5 = 5[tex]\frac{14}{93}[/tex]
6[tex]\frac{17}{41}[/tex]+7[tex]\frac{19}{41}[/tex]=[tex](6+7)\frac{17+19}{41}[/tex]=[tex]13\frac{36}{41}[/tex]
(24-17)[tex]\frac{9-5}{38}[/tex]=[tex]7\frac{4}{38}[/tex]
(7+2)[tex]\frac{14+1}{15}[/tex]=9[tex]\frac{15}{15}[/tex]=10
(9+12)[tex]\frac{24+13}{27}[/tex]=[tex]21\frac{37}{27}[/tex]=[tex]22\frac{10}{27}[/tex]
[tex]1- \frac{12}{19}[/tex]=[tex]\frac{19}{19} -\frac{12}{19}[/tex]=[tex]\frac{7}{19}[/tex]
[tex]8-3\frac{6}{15} = 7\frac{15}{15}-3\frac{6}{15} = 4\frac{9}{15}[/tex]
[tex]16\frac{3}{13} -6\frac{8}{13} = 15\frac{16}{13} -6\frac{8}{13} = 9\frac{8}{13}[/tex]
№2
25-x=[tex]8\frac{3}{14}[/tex] [tex]25-8\frac{3}{14}[/tex]=x x=[tex]24\frac{14}{14} -8\frac{3}{14}=16\frac{11}{14}[/tex]
[tex]7\frac{7}{30} -(5\frac{11}{30}-y)=3\frac{19}{30}[/tex] [tex]7\frac{7}{30} -5\frac{11}{30}+y=3\frac{19}{30}[/tex] [tex]y=3\frac{19}{30}-7\frac{7}{30} + 5\frac{11}{30}[/tex] [tex]y=(3+5-7)\frac{19-7+11}{30}=1\frac{23}{30}[/tex]
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Answers & Comments
Ответ:
Пошаговое объяснение:
№1
[tex]\frac{14}{93}[/tex]+5 = 5[tex]\frac{14}{93}[/tex]
6[tex]\frac{17}{41}[/tex]+7[tex]\frac{19}{41}[/tex]=[tex](6+7)\frac{17+19}{41}[/tex]=[tex]13\frac{36}{41}[/tex]
(24-17)[tex]\frac{9-5}{38}[/tex]=[tex]7\frac{4}{38}[/tex]
(7+2)[tex]\frac{14+1}{15}[/tex]=9[tex]\frac{15}{15}[/tex]=10
(9+12)[tex]\frac{24+13}{27}[/tex]=[tex]21\frac{37}{27}[/tex]=[tex]22\frac{10}{27}[/tex]
[tex]1- \frac{12}{19}[/tex]=[tex]\frac{19}{19} -\frac{12}{19}[/tex]=[tex]\frac{7}{19}[/tex]
[tex]8-3\frac{6}{15} = 7\frac{15}{15}-3\frac{6}{15} = 4\frac{9}{15}[/tex]
[tex]16\frac{3}{13} -6\frac{8}{13} = 15\frac{16}{13} -6\frac{8}{13} = 9\frac{8}{13}[/tex]
№2
25-x=[tex]8\frac{3}{14}[/tex] [tex]25-8\frac{3}{14}[/tex]=x x=[tex]24\frac{14}{14} -8\frac{3}{14}=16\frac{11}{14}[/tex]
[tex]7\frac{7}{30} -(5\frac{11}{30}-y)=3\frac{19}{30}[/tex] [tex]7\frac{7}{30} -5\frac{11}{30}+y=3\frac{19}{30}[/tex] [tex]y=3\frac{19}{30}-7\frac{7}{30} + 5\frac{11}{30}[/tex] [tex]y=(3+5-7)\frac{19-7+11}{30}=1\frac{23}{30}[/tex]