4(х-6)(х+11) = 0 | : 4

(х-6)(х+11) = 0

х-6 = 0 або х+11 = 0

х = 6 або х = -11

В

[tex]a {x}^{2} + bx + c = a(x - x_{1})(x - x_{2}) \\ 4(x - 6)(x + 11) = 0 \\ x_{1} = 6\\ x_{2} = - 11 [/tex]