[tex] - \frac{ x+ 4}{4} + \frac{3(x + 8)}{8} = \frac{2x + 32}{16} \\ \frac{ - 2x - 8 + 3x + 24}{8} = \frac{2x + 32}{16} \\ \frac{x + 16}{8} = \frac{2x + 32}{16} \\ 16x + 256 = 16x + 256[/tex]
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[tex] - \frac{ x+ 4}{4} + \frac{3(x + 8)}{8} = \frac{2x + 32}{16} \\ \frac{ - 2x - 8 + 3x + 24}{8} = \frac{2x + 32}{16} \\ \frac{x + 16}{8} = \frac{2x + 32}{16} \\ 16x + 256 = 16x + 256[/tex]