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bela200473
@bela200473
July 2022
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1.Найдите ординату точки с абсциссой 10, лежащий на графике 4/5х-2у=10
2.Найдите ординату точки с абсциссой 20 , лежащий на графике функции 4/5х-2у=10
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sofiyavictoria
1). 4/5*10-2у=10
8-2у=10. -2у=2= у=-1
2). 4/5*20-2у=10
16-2у=10. -2у=-6. у=3
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Answers & Comments
8-2у=10. -2у=2= у=-1
2). 4/5*20-2у=10
16-2у=10. -2у=-6. у=3