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Евгений235
@Евгений235
December 2021
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преобразуйте выражение в многочлен:а)(2а-1)^2;б)(х+3у)^2;в)(1/5х-у)(1/5х+у);
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Kixcertborn2
Verified answer
а)(2а-1)
²=(2a)²-2*2a*1+1²=4a²-4a+1
============================================================
б)(х+3у)^2==x
²+2x*3y+(3y)²=x²+6xy+9y²
============================================================
в)(1/5х-у)(1/5х+у)=(1/5x)
²-y²=1/25x²-y²
============================================================
1 votes
Thanks 2
Евгений235
А откуда появилось 282 в первом выражении
Kixcertborn2
это умножить)
Евгений235
2*2а*1-я правильно понял
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Answers & Comments
Verified answer
а)(2а-1)²=(2a)²-2*2a*1+1²=4a²-4a+1============================================================
б)(х+3у)^2==x²+2x*3y+(3y)²=x²+6xy+9y²
============================================================
в)(1/5х-у)(1/5х+у)=(1/5x)²-y²=1/25x²-y²
============================================================