sinB=AC/AB
4/5=AC/5
AC=4*5/5=4
По теореме Пифагора:
AC^2+BC^2=AB^2
BC^2=AB^2-AC^2
BC=√(AB^2-AC^2)
BC=√(5^2-4^2)=√(25-16)=√9=3
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sinB=AC/AB
4/5=AC/5
AC=4*5/5=4
По теореме Пифагора:
AC^2+BC^2=AB^2
BC^2=AB^2-AC^2
BC=√(AB^2-AC^2)
BC=√(5^2-4^2)=√(25-16)=√9=3