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nastya11001
@nastya11001
July 2022
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ПОМОГИТЕ!!!!
1)Вычислите:
cos0.3 + cos(п - 0.3) - sin²2 - cos²2
2)Определите знак выражения:
cos(-7п/9)ctg* 12п/5*tg3
3)Cравните числа a и d,если a=cos6,d=sin6
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m11m
Verified answer
1) cos0.3+cos(п-0,3)-sin²2 -cos²2=
=cos0.3-cos0.3-(sin²2+cos²2)=0-1= -1
2) cos(-7п/9)=cos(7п/9)=cos(п - 2п/9)= - cos(2п/9)= " - " (знак минус)
ctg(12п/5)=ctg(2п + 2п/5)=ctg(2п/5)= " + "
tg3= tg((3*180)/3.14)≈tg171°≈tg(180°-9°)= -tg9° = " - "
" - " * " + " * " - "= " + "
Ответ: выражение имеет знак " + ".
3) a=cos6 d=sin6
6 = (6*180)/3,14≈344° ≈ 360° - 16°
cos6=cos(360° - 16°)=cos16°
sin6=sin(360° - 16°)= - sin16°
cos16° > sin16°
cos6 > sin6
a > d
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Answers & Comments
Verified answer
1) cos0.3+cos(п-0,3)-sin²2 -cos²2==cos0.3-cos0.3-(sin²2+cos²2)=0-1= -1
2) cos(-7п/9)=cos(7п/9)=cos(п - 2п/9)= - cos(2п/9)= " - " (знак минус)
ctg(12п/5)=ctg(2п + 2п/5)=ctg(2п/5)= " + "
tg3= tg((3*180)/3.14)≈tg171°≈tg(180°-9°)= -tg9° = " - "
" - " * " + " * " - "= " + "
Ответ: выражение имеет знак " + ".
3) a=cos6 d=sin6
6 = (6*180)/3,14≈344° ≈ 360° - 16°
cos6=cos(360° - 16°)=cos16°
sin6=sin(360° - 16°)= - sin16°
cos16° > sin16°
cos6 > sin6
a > d